How to Find the Area of a Trapezium with No Parallel Sides
Break down the trapezium into two triangles., Find the values for a{\displaystyle a}, b{\displaystyle b}, and c{\displaystyle c} for both triangles A and B where a{\displaystyle a}= the included angle of the sides a{\displaystyle a} and...
Step-by-Step Guide
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Step 1: Break down the trapezium into two triangles.
Label your triangles as triangle A and triangle B.
Look at the picture for help.(The image does not scale.) , (Example values are below their pictures) Triangle A: a{\displaystyle a}=70, b{\displaystyle b}=13, and c{\displaystyle c}=15.
Triangle B: a{\displaystyle a}=91, b{\displaystyle b}=11, and c{\displaystyle c}=9. , Plug the values from the second step in the formula.
Triangle A:
A=bc/2(sin∗a)=(13)(15)/2(sin70)≈45.8101{\displaystyle A=bc/2(sin*a)=(13)(15)/2(sin70)\approx
45.8101} Triangle B:
A=bc/2(sin∗a)=(11)(9)/2(sin91)≈49.4901{\displaystyle A=bc/2(sin*a)=(11)(9)/2(sin91)\approx
49.4901} , That is your final answer!
45.8101+49.4901=95.7102.A≈95.7102{\displaystyle
45.8101+49.4901=95.7102.A\approx
95.7102} -
Step 2: Find the values for a{\displaystyle a}
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Step 3: b{\displaystyle b}
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Step 4: and c{\displaystyle c} for both triangles A and B where a{\displaystyle a}= the included angle of the sides a{\displaystyle a} and b{\displaystyle b}
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Step 5: b{\displaystyle b}= one of the two sides that you know
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Step 6: and c{\displaystyle c}= the other side that you know.
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Step 7: Use the formula A=bc/2(sin∗a){\displaystyle A=bc/2(sin*a)} to calculate the areas of the triangles.
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Step 8: Add the areas for the triangles A and B.
Detailed Guide
Label your triangles as triangle A and triangle B.
Look at the picture for help.(The image does not scale.) , (Example values are below their pictures) Triangle A: a{\displaystyle a}=70, b{\displaystyle b}=13, and c{\displaystyle c}=15.
Triangle B: a{\displaystyle a}=91, b{\displaystyle b}=11, and c{\displaystyle c}=9. , Plug the values from the second step in the formula.
Triangle A:
A=bc/2(sin∗a)=(13)(15)/2(sin70)≈45.8101{\displaystyle A=bc/2(sin*a)=(13)(15)/2(sin70)\approx
45.8101} Triangle B:
A=bc/2(sin∗a)=(11)(9)/2(sin91)≈49.4901{\displaystyle A=bc/2(sin*a)=(11)(9)/2(sin91)\approx
49.4901} , That is your final answer!
45.8101+49.4901=95.7102.A≈95.7102{\displaystyle
45.8101+49.4901=95.7102.A\approx
95.7102}
About the Author
Cynthia Long
Experienced content creator specializing in cooking guides and tutorials.
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