How to Solve Quadratic Equations with the "Transforming Method"

Recall the Rule of Signs., Transform the equation in standard form ax^2 + bx + c = 0 (1) into a new equation, with a = 1, and the constant C = a*c. The new equation has the form: x^2 + bx + a*c = 0, (2). , Solve the transformed equation (2) by the...

10 Steps 3 min read Medium

Step-by-Step Guide

  1. Step 1: Recall the Rule of Signs.

    If a and c have different signs, roots have different signs If a and c have same sign, roots have same sign.

    If a and b have different signs, both roots are positive.

    If a and b have same sign, both roots are negative.
  2. Step 2: Transform the equation in standard form ax^2 + bx + c = 0 (1) into a new equation

    , Solving results in finding 2 numbers knowing the sum (-b) and the product (a*c).

    Compose factor pairs of a*c following these 2 Tips below.

    Find the pair that equals to (-b), or b.

    If you can't find this pair, this means the equation can't be factored, and you should probably solve it by the Quadratic Formula.

    If roots have different signs (a and c different signs), compose factor pairs of a*c with all first numbers being negative.

    If roots have same sign (a and c same sign), compose factor pairs of a*c: with all negative numbers when both roots are negative. with all positive numbers when both roots are positive.

    Example
    1.

    Solve: x^2
    - 11x
    - 102 =
    0.

    Roots have different signs.

    Compose factor pairs of c =
    -102 with all first numbers being negative.

    Proceeding: (-1, 102)(-2, 51)(-3, 34)(--6, 17).

    This last sum is: 17
    - 6 = 11 =
    -b.

    Then, the 2 real roots are:
    -6 and
    17.

    No factoring and solving binomials.

    Example
    2.

    Solve: x^2 + 39x + 108 =
    0.

    Both roots are negative.

    Compose factor pairs of c = 108 with all negative numbers.

    Proceeding: (-1,
    -108)(-2,
    -54)(-3,
    -36).

    This last sum is
    -39 =
    -b.

    Then, the 2 real roots are:
    -3, and
    -36. " Example 3".

    Solve: x^2
    - 23x + 102 =
    0.

    Both roots are positive.

    Compose factor pairs of c = 102 with all positive numbers.

    Proceeding: (1, 102)(2, 51)(3, 34)(6, 17).

    This last sum is: 17 + 6 = 23 =
    -b.

    The 2 real roots are: 6 and
    17. ,, Examples of solving by the new "Transforming Method" Example
    3.

    Original equation to solve: 6x^2
    - 19x
    - 11 =
    0. (1).

    First, solve the transformed equation: x^2
    - 19x
    - 66 =
    0.(2).

    Roots have different signs.

    Compose factor pairs of a*c =
    -66.

    Proceeding: (-1, 66)(-2, 33)(-3, 22).

    This last sum is 22
    - 3 = 19 =
    -b.

    Then, the 2 real roots of (2) is: y1 =
    -3, and y2 =
    22.

    Next, divide both y1, and y2 by a =
    6.

    The 2 real roots of the original equation (1) are: x1 = y1/6 =
    -3/6 =
    -1/2, and x2 = y2/6 = 22/6 = 11/3.

    Example
    4.

    Original equation to solve: 6x^2
    - 11x
    - 35 = 0 (1). , Roots have different signs.

    To save time, compose factor pairs from the middle of the factor chain.

    Proceeding: .....(-5, 42)(-7, 30)(-10, 21).

    This last sum is: 21
    - 10 = 11 =
    -b.

    Then, y1 =
    -10, and y2 =
    21.

    Next, find the 2 real roots of the original equation (1): x1 = y1/6 =
    -10/6 =
    -5/3, and x2 = 21/6 = 7/2..

    Example
    5.

    Original equation: 12x^2 + 29x + 15 =
    0. (1).

    Solve transformed equation: x^2 + 29x + 180 = 0 (2).

    Both roots are negative.

    Start composing a*c = 180 from the middle of the factor chain.

    Proceeding:..... (-5,
    -36)(-6,
    -30)(-9,
    -20).

    This last sum is:
    -29 =
    -b.

    The 2 real roots of (2) are: y1 =
    -9, and y2 =
    -20.

    Next, find the 2 real roots of (1): x1 =
    -9/12 =
    -3/4, and x2 =
    -20/12 =
    -5/3.
  3. Step 3: with a = 1

  4. Step 4: and the constant C = a*c. The new equation has the form: x^2 + bx + a*c = 0

  5. Step 5: Solve the transformed equation (2) by the Diagonal Sum Method that can immediately obtain the 2 real roots.

  6. Step 6: Assume that the 2 real roots of the simplified equation (2) are: y1

  7. Step 7: and y2.

  8. Step 8: Divide both real roots y1 and y2 by the coefficient a to get the 2 real roots x1

  9. Step 9: and x2 of the original equation (1).

  10. Step 10: Solve the transformed equation: x^2 - 11x - 210 = 0 (2).

Detailed Guide

If a and c have different signs, roots have different signs If a and c have same sign, roots have same sign.

If a and b have different signs, both roots are positive.

If a and b have same sign, both roots are negative.

, Solving results in finding 2 numbers knowing the sum (-b) and the product (a*c).

Compose factor pairs of a*c following these 2 Tips below.

Find the pair that equals to (-b), or b.

If you can't find this pair, this means the equation can't be factored, and you should probably solve it by the Quadratic Formula.

If roots have different signs (a and c different signs), compose factor pairs of a*c with all first numbers being negative.

If roots have same sign (a and c same sign), compose factor pairs of a*c: with all negative numbers when both roots are negative. with all positive numbers when both roots are positive.

Example
1.

Solve: x^2
- 11x
- 102 =
0.

Roots have different signs.

Compose factor pairs of c =
-102 with all first numbers being negative.

Proceeding: (-1, 102)(-2, 51)(-3, 34)(--6, 17).

This last sum is: 17
- 6 = 11 =
-b.

Then, the 2 real roots are:
-6 and
17.

No factoring and solving binomials.

Example
2.

Solve: x^2 + 39x + 108 =
0.

Both roots are negative.

Compose factor pairs of c = 108 with all negative numbers.

Proceeding: (-1,
-108)(-2,
-54)(-3,
-36).

This last sum is
-39 =
-b.

Then, the 2 real roots are:
-3, and
-36. " Example 3".

Solve: x^2
- 23x + 102 =
0.

Both roots are positive.

Compose factor pairs of c = 102 with all positive numbers.

Proceeding: (1, 102)(2, 51)(3, 34)(6, 17).

This last sum is: 17 + 6 = 23 =
-b.

The 2 real roots are: 6 and
17. ,, Examples of solving by the new "Transforming Method" Example
3.

Original equation to solve: 6x^2
- 19x
- 11 =
0. (1).

First, solve the transformed equation: x^2
- 19x
- 66 =
0.(2).

Roots have different signs.

Compose factor pairs of a*c =
-66.

Proceeding: (-1, 66)(-2, 33)(-3, 22).

This last sum is 22
- 3 = 19 =
-b.

Then, the 2 real roots of (2) is: y1 =
-3, and y2 =
22.

Next, divide both y1, and y2 by a =
6.

The 2 real roots of the original equation (1) are: x1 = y1/6 =
-3/6 =
-1/2, and x2 = y2/6 = 22/6 = 11/3.

Example
4.

Original equation to solve: 6x^2
- 11x
- 35 = 0 (1). , Roots have different signs.

To save time, compose factor pairs from the middle of the factor chain.

Proceeding: .....(-5, 42)(-7, 30)(-10, 21).

This last sum is: 21
- 10 = 11 =
-b.

Then, y1 =
-10, and y2 =
21.

Next, find the 2 real roots of the original equation (1): x1 = y1/6 =
-10/6 =
-5/3, and x2 = 21/6 = 7/2..

Example
5.

Original equation: 12x^2 + 29x + 15 =
0. (1).

Solve transformed equation: x^2 + 29x + 180 = 0 (2).

Both roots are negative.

Start composing a*c = 180 from the middle of the factor chain.

Proceeding:..... (-5,
-36)(-6,
-30)(-9,
-20).

This last sum is:
-29 =
-b.

The 2 real roots of (2) are: y1 =
-9, and y2 =
-20.

Next, find the 2 real roots of (1): x1 =
-9/12 =
-3/4, and x2 =
-20/12 =
-5/3.

About the Author

S

Sharon Davis

Experienced content creator specializing in cooking guides and tutorials.

82 articles
View all articles

Rate This Guide

--
Loading...
5
0
4
0
3
0
2
0
1
0

How helpful was this guide? Click to rate: