How to Solve Quadratic Equations with the "Transforming Method"
Recall the Rule of Signs., Transform the equation in standard form ax^2 + bx + c = 0 (1) into a new equation, with a = 1, and the constant C = a*c. The new equation has the form: x^2 + bx + a*c = 0, (2). , Solve the transformed equation (2) by the...
Step-by-Step Guide
-
Step 1: Recall the Rule of Signs.
If a and c have different signs, roots have different signs If a and c have same sign, roots have same sign.
If a and b have different signs, both roots are positive.
If a and b have same sign, both roots are negative. -
Step 2: Transform the equation in standard form ax^2 + bx + c = 0 (1) into a new equation
, Solving results in finding 2 numbers knowing the sum (-b) and the product (a*c).
Compose factor pairs of a*c following these 2 Tips below.
Find the pair that equals to (-b), or b.
If you can't find this pair, this means the equation can't be factored, and you should probably solve it by the Quadratic Formula.
If roots have different signs (a and c different signs), compose factor pairs of a*c with all first numbers being negative.
If roots have same sign (a and c same sign), compose factor pairs of a*c: with all negative numbers when both roots are negative. with all positive numbers when both roots are positive.
Example
1.
Solve: x^2
- 11x
- 102 =
0.
Roots have different signs.
Compose factor pairs of c =
-102 with all first numbers being negative.
Proceeding: (-1, 102)(-2, 51)(-3, 34)(--6, 17).
This last sum is: 17
- 6 = 11 =
-b.
Then, the 2 real roots are:
-6 and
17.
No factoring and solving binomials.
Example
2.
Solve: x^2 + 39x + 108 =
0.
Both roots are negative.
Compose factor pairs of c = 108 with all negative numbers.
Proceeding: (-1,
-108)(-2,
-54)(-3,
-36).
This last sum is
-39 =
-b.
Then, the 2 real roots are:
-3, and
-36. " Example 3".
Solve: x^2
- 23x + 102 =
0.
Both roots are positive.
Compose factor pairs of c = 102 with all positive numbers.
Proceeding: (1, 102)(2, 51)(3, 34)(6, 17).
This last sum is: 17 + 6 = 23 =
-b.
The 2 real roots are: 6 and
17. ,, Examples of solving by the new "Transforming Method" Example
3.
Original equation to solve: 6x^2
- 19x
- 11 =
0. (1).
First, solve the transformed equation: x^2
- 19x
- 66 =
0.(2).
Roots have different signs.
Compose factor pairs of a*c =
-66.
Proceeding: (-1, 66)(-2, 33)(-3, 22).
This last sum is 22
- 3 = 19 =
-b.
Then, the 2 real roots of (2) is: y1 =
-3, and y2 =
22.
Next, divide both y1, and y2 by a =
6.
The 2 real roots of the original equation (1) are: x1 = y1/6 =
-3/6 =
-1/2, and x2 = y2/6 = 22/6 = 11/3.
Example
4.
Original equation to solve: 6x^2
- 11x
- 35 = 0 (1). , Roots have different signs.
To save time, compose factor pairs from the middle of the factor chain.
Proceeding: .....(-5, 42)(-7, 30)(-10, 21).
This last sum is: 21
- 10 = 11 =
-b.
Then, y1 =
-10, and y2 =
21.
Next, find the 2 real roots of the original equation (1): x1 = y1/6 =
-10/6 =
-5/3, and x2 = 21/6 = 7/2..
Example
5.
Original equation: 12x^2 + 29x + 15 =
0. (1).
Solve transformed equation: x^2 + 29x + 180 = 0 (2).
Both roots are negative.
Start composing a*c = 180 from the middle of the factor chain.
Proceeding:..... (-5,
-36)(-6,
-30)(-9,
-20).
This last sum is:
-29 =
-b.
The 2 real roots of (2) are: y1 =
-9, and y2 =
-20.
Next, find the 2 real roots of (1): x1 =
-9/12 =
-3/4, and x2 =
-20/12 =
-5/3. -
Step 3: with a = 1
-
Step 4: and the constant C = a*c. The new equation has the form: x^2 + bx + a*c = 0
-
Step 5: Solve the transformed equation (2) by the Diagonal Sum Method that can immediately obtain the 2 real roots.
-
Step 6: Assume that the 2 real roots of the simplified equation (2) are: y1
-
Step 7: and y2.
-
Step 8: Divide both real roots y1 and y2 by the coefficient a to get the 2 real roots x1
-
Step 9: and x2 of the original equation (1).
-
Step 10: Solve the transformed equation: x^2 - 11x - 210 = 0 (2).
Detailed Guide
If a and c have different signs, roots have different signs If a and c have same sign, roots have same sign.
If a and b have different signs, both roots are positive.
If a and b have same sign, both roots are negative.
, Solving results in finding 2 numbers knowing the sum (-b) and the product (a*c).
Compose factor pairs of a*c following these 2 Tips below.
Find the pair that equals to (-b), or b.
If you can't find this pair, this means the equation can't be factored, and you should probably solve it by the Quadratic Formula.
If roots have different signs (a and c different signs), compose factor pairs of a*c with all first numbers being negative.
If roots have same sign (a and c same sign), compose factor pairs of a*c: with all negative numbers when both roots are negative. with all positive numbers when both roots are positive.
Example
1.
Solve: x^2
- 11x
- 102 =
0.
Roots have different signs.
Compose factor pairs of c =
-102 with all first numbers being negative.
Proceeding: (-1, 102)(-2, 51)(-3, 34)(--6, 17).
This last sum is: 17
- 6 = 11 =
-b.
Then, the 2 real roots are:
-6 and
17.
No factoring and solving binomials.
Example
2.
Solve: x^2 + 39x + 108 =
0.
Both roots are negative.
Compose factor pairs of c = 108 with all negative numbers.
Proceeding: (-1,
-108)(-2,
-54)(-3,
-36).
This last sum is
-39 =
-b.
Then, the 2 real roots are:
-3, and
-36. " Example 3".
Solve: x^2
- 23x + 102 =
0.
Both roots are positive.
Compose factor pairs of c = 102 with all positive numbers.
Proceeding: (1, 102)(2, 51)(3, 34)(6, 17).
This last sum is: 17 + 6 = 23 =
-b.
The 2 real roots are: 6 and
17. ,, Examples of solving by the new "Transforming Method" Example
3.
Original equation to solve: 6x^2
- 19x
- 11 =
0. (1).
First, solve the transformed equation: x^2
- 19x
- 66 =
0.(2).
Roots have different signs.
Compose factor pairs of a*c =
-66.
Proceeding: (-1, 66)(-2, 33)(-3, 22).
This last sum is 22
- 3 = 19 =
-b.
Then, the 2 real roots of (2) is: y1 =
-3, and y2 =
22.
Next, divide both y1, and y2 by a =
6.
The 2 real roots of the original equation (1) are: x1 = y1/6 =
-3/6 =
-1/2, and x2 = y2/6 = 22/6 = 11/3.
Example
4.
Original equation to solve: 6x^2
- 11x
- 35 = 0 (1). , Roots have different signs.
To save time, compose factor pairs from the middle of the factor chain.
Proceeding: .....(-5, 42)(-7, 30)(-10, 21).
This last sum is: 21
- 10 = 11 =
-b.
Then, y1 =
-10, and y2 =
21.
Next, find the 2 real roots of the original equation (1): x1 = y1/6 =
-10/6 =
-5/3, and x2 = 21/6 = 7/2..
Example
5.
Original equation: 12x^2 + 29x + 15 =
0. (1).
Solve transformed equation: x^2 + 29x + 180 = 0 (2).
Both roots are negative.
Start composing a*c = 180 from the middle of the factor chain.
Proceeding:..... (-5,
-36)(-6,
-30)(-9,
-20).
This last sum is:
-29 =
-b.
The 2 real roots of (2) are: y1 =
-9, and y2 =
-20.
Next, find the 2 real roots of (1): x1 =
-9/12 =
-3/4, and x2 =
-20/12 =
-5/3.
About the Author
Sharon Davis
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